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= Hilos resueltos
HELLO EVERYONE.
I have a CAN network wiring situation, where I have 8 modules in the same network.
Physically the cleanest way to assemble it would be to crimp 5 modules and a continuation for the other 3 in a similar format to an X, where the 5 would be crimped at a single point.
I don't think it's ideal, but physically it would be the best option!
Can you alert me to any point that causes problems?
Thank's
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WhatsApp-Image-2025-01-16-at-10.21.39.jpeg
this way you have 5 CAN crimp looms in a single pair.
show in the image
I will send an image below with another more correct option, but the distance is extremely short.
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- WhatsApp-Image-2025-01-16-at-10.39.56.jpeg
the second option makes me more comfortable
Can you update your diagram with the length of each leg?
Yes.
at point FT700 B, there is an internal resistor.
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I believe what you have drawn should work fine because the distances are short. However, this what I would do if that were my layout. The Red line represents the twisted pair CAN bus:
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- CAN-Network-Wiring.jpg
@david Ferguson in your updated drawing, with the suggested red line representing wire routing, would you simply crimp two conductors into each terminal at each node? Effectively splicing the CAN_H "in" and "out" wire at the Steering node connector, as well as the CAN_L "in" and "out" conductors?
Yes, that is the easiest way if the contact supports it. I use mostly DTM, and I can put 2 22ga wires into one terminal. Otherwise I would do a 3-way splice 2" from the connector.
